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traditional = [
(1024 ** 5, 'P'),
(1024 ** 4, 'T'),
(1024 ** 3, 'G'),
(1024 ** 2, 'M'),
(1024 ** 1, 'K'),
(1024 ** 0, 'B'),
]
alternative = [
(1024 ** 5, ' PB'),
(1024 ** 4, ' TB'),
(1024 ** 3, ' GB'),
(1024 ** 2, ' MB'),
(1024 ** 1, ' KB'),
(1024 ** 0, (' byte', ' bytes')),
]
verbose = [
(1024 ** 5, (' petabyte', ' petabytes')),
(1024 ** 4, (' terabyte', ' terabytes')),
(1024 ** 3, (' gigabyte', ' gigabytes')),
(1024 ** 2, (' megabyte', ' megabytes')),
(1024 ** 1, (' kilobyte', ' kilobytes')),
(1024 ** 0, (' byte', ' bytes')),
]
iec = [
(1024 ** 5, 'Pi'),
(1024 ** 4, 'Ti'),
(1024 ** 3, 'Gi'),
(1024 ** 2, 'Mi'),
(1024 ** 1, 'Ki'),
(1024 ** 0, ''),
]
si = [
(1000 ** 5, 'P'),
(1000 ** 4, 'T'),
(1000 ** 3, 'G'),
(1000 ** 2, 'M'),
(1000 ** 1, 'K'),
(1000 ** 0, 'B'),
]
def size(bytes, system=traditional):
"""Human-readable file size.
Using the traditional system, where a factor of 1024 is used::
>>> size(10)
'10B'
>>> size(100)
'100B'
>>> size(1000)
'1000B'
>>> size(2000)
'1K'
>>> size(10000)
'9K'
>>> size(20000)
'19K'
>>> size(100000)
'97K'
>>> size(200000)
'195K'
>>> size(1000000)
'976K'
>>> size(2000000)
'1M'
Using the SI system, with a factor 1000::
>>> size(10, system=si)
'10B'
>>> size(100, system=si)
'100B'
>>> size(1000, system=si)
'1K'
>>> size(2000, system=si)
'2K'
>>> size(10000, system=si)
'10K'
>>> size(20000, system=si)
'20K'
>>> size(100000, system=si)
'100K'
>>> size(200000, system=si)
'200K'
>>> size(1000000, system=si)
'1M'
>>> size(2000000, system=si)
'2M'
"""
for factor, suffix in system:
if bytes >= factor:
break
amount = int(bytes/factor)
if isinstance(suffix, tuple):
singular, multiple = suffix
if amount == 1:
suffix = singular
else:
suffix = multiple
return str(amount) + suffix